K
kumar_eee
Guest
RAM dogovoru čipov v matriki 4x6 in 8kX4bit zmogljivosti vsakega.Koliko vrstic reqd naslov.za dostop do posamezne byte
a.12
b.16
c.15
d.17
a.12
b.16
c.15
d.17
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J
jraks
Guest
Zdaj 8k * 4 = 32kbits, 32k/1byteor8bits = 4kbytes
skupni pomnilnik = 4 * 6 * 4k = 96k ~ == 100kbytes
Zato 100kB == 2 ^ 16 2 ^ 15
tako da bi na koncu rekel 15 vrstic, bi se naslov rquired za dostop do ene od bajtov pomnilnika
skupni pomnilnik = 4 * 6 * 4k = 96k ~ == 100kbytes
Zato 100kB == 2 ^ 16 2 ^ 15
tako da bi na koncu rekel 15 vrstic, bi se naslov rquired za dostop do ene od bajtov pomnilnika
T
tamerakshar
Guest
to ni pravilen odgovor, njen spomin arraypreverite back vaša rešitev človek
J
jraks
Guest
lets see
ckecking it out
ckecking it out